Question

1/(1 + sinA) + 1/(1 - sinA) = 2sec²A​

Answer 1

$\huge{ \underline{ \overline{ \mid{ \mathcal{Answer}} \mid}}}$

$= \sf\dfrac{1}{(1 + sinA} + \dfrac{1}{(1 - sinA)}$

$= \sf\dfrac{1 - sinA + 1 + sinA}{(1 + sinA)(1 - sinA)}$

$(a + b)(a - b) = a² - b²</p><p> \\ \\ = \sf\dfrac{2}{ 1 - sin²A}$

$1 - sin²A = cos²A</p><p>= \sf\dfrac{2}{cos²A}$

$= 2 \:sec²$

Answer 2

Answer:

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Step-by-step explanation:

she has given u the answer