Question

1/1-sinA+1/1+sinA=2secsquare

Answer 1

I hope answer is helpful for you

Answer 2

HEY Buddy......!! here is ur answer

We have to prove that.......

[1/(1–sinA)] + [1/(1+sinA)] = 2sec²A

On taking L.H.S. =>

=> (1+sinA+1–sinA)/(1–sinA)(1+sinA)

=> 2/1–sin²A { (a-b)(a+b) = a²–b²}

=> 2/cos²A { sin²A+cos²A = 1 => 1-sin²A=cos²A}

=> 2sec²A = R.H.S. { cosA = 1/secA }

I hope it will be helpful for you.....!!

THANK YOU ✌️✌️