1)(1 st number)^2nd number = (2 nd number)^1 st number ,
Show that 2nd number × log( 1st number)= 1st number × log (2 nd number).
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well I assume that 1st no is x and 2nd no is y
so question becomes
x power y = y power x
taking log both sides
⇒log(x power y) = log( y power x)
using properties of log
⇒ y logx = x logy hence proved
hope u understand
so question becomes
x power y = y power x
taking log both sides
⇒log(x power y) = log( y power x)
using properties of log
⇒ y logx = x logy hence proved
hope u understand
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