1/(1-x)^2 dx. find the integral of this
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Answer:
good morning .
but i don't know the answer because I don't know how to find integral ....
Answered by
1
Property of integration
∫e
x
(f(x)+f
′
(x))dx=e
x
f(x)+c
Let f(x)=
x
1
Differentiating f
′
(x)=−
x
2
1
∴∫e
x
(
x
1
−
x
2
1
)dx=∫e
x
[
x
1
+(−
x
2
1
)]dx
=e
x
.
x
1
+c
∫e
x
(
x
1
−
x
2
1
)dx=
x
e
x
+c
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