1. અવયવો પાડો :
( 1 ) xy + xz + yz + z²
(3 ) x² + 2x + xy + 2y
(5) xy - 4x + 3y - 12
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Answer:
(1) xy + xz + yz + z² = x(y + z) + z(y + z)
= (y + z)(x + z)
(2) x² + 2x + xy + 2y = x(x + 2) + y(x + 2)
= (x + 2)(x + y)
(3) xy - 4x + 3y - 12 = x(y - 4) + 3(y - 4)
= (y - 4)(x + 3)
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