Question

1
10-4 mho cm
98. 0.04 N solution of a weak acid has specific corductance 4.23 x
and degree of dissociation is 0.0612. The
equivalent conductance (Ohm em equiv l) of weak acid at
infinite dilution is solve​

Answer 1

Given:

0.04 N solution of a weak acid has specific conductance 4.23 × 10−4 mho cm−1 and degree of dissociation is 0.0612.

To find:

The equivalent conductance (Ohm em equiv l) of weak acid at infinite dilution.

Solution:

From the given information, we have the data as follows.

0.04 N solution of a weak acid has specific conductance 4.23 × 10−4 mho cm−1 and degree of dissociation is 0.0612.

A = k × 1000/N

A = 4.23 × 10^-4 × 1000/0.04

A = 10.575

α = A/A∞

⇒ A∞ = A/α

A∞ = 10.575/0.0612

∴ A∞ = 172.79

Therefore, the equivalent conductivity at infinite dilution is 172.79