Question

-1×10^-6 is on a drop of water having mass 10^-6 kg what electric field should be applied on the drop so that it is in the balanced condition with its weight

Answer 1

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to obtain balance condition

F = Mg

qE = Mg

-1 X 10^-6 X E = 10^-6 X 10

from this you will get the value of E

E = -10

where (-) ve sign indicates the direction

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