Question

1.
10 g of a fairly conc. solution of Cuso4, is
electrolysed using 0.01 faraday of electricity. The
weight of solution after electrolysis

(1) 9.6
(2) 10 9
(3) 9.75 g
(4) 0 39 g​

Answer 1

Cu²+ 2e- → Cu

so, 1 faraday deposits 0.5 mole of Cu

0.01 faraday deposits Cu = 0.5∗0.01 = 0.005 mole

1 mole of Cu = 63.5 g

0.005 mole = 0.3175 g of Cu

so, the mass of resulting solution = 10−0.31

the mass of resulting solution= 9.6

please mark as brainliest

Answer 2

Explanation:

the answer is(2)10 9 I don't know it will be right or wrong if it is wrong I am so sorry