Question

1. 10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of 8 water produced in this reaction will be: (a) 3 mol (b) 4 mol (c) 1 mol (d)2 mol​

Answer 1

Answer:

4 mol

2H  

2

​

+O  

2

​

→2H  

2

​

O

10 g of hydrogen (molar mass 2 g/mol) =  

2 g/mol  

10 g  

​

= 5 mol  

64 of oxygen  (molar mass 32 g/mol) =  

32 g/mol  

64 g  

​

= 2 mol  

As per the balanced chemical equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water.

2 moles of oxygen will react with 2×2=4 moles of hydrogen to form 4 moles of water.

Here, oxygen is the limiting reagent and hydrogen is the excess reagent.

Hence, option B is correct.