1 + 10 theta whole square + 1 - 10 theta whole square is equal to 2 sec square theta
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23
Step-by-step explanation:
(1+tanθ)^2 + (1-tanθ)^2
=1+(tanθ)^2 +2tanθ+1+(tanθ)^2-2tanθ
=1+(tanθ)^2+1+(tanθ)^2
2(secθ)^2. {1+(tanθ)^2 = (secθ)^2}
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4
Step-by-step explanation:
expjained in the above pic plz mark it the btainliest
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