1) 10÷x+y +2÷x-y=4
15÷x+y -5÷x-y=-2
solve it by reducing to linear equation
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Answered by
0
x+y=2xy
x-y=6xy
x=-1/2
y=1/4
x-y=6xy
x=-1/2
y=1/4
Answered by
2
Hiii friend,
10/X+Y + 2/X-Y = 4-------(1)
15/X+Y - 5/X-Y = -2--------(2)
Let 1/X+Y = U and 1/X-Y = V . Then equation (1) and equation (2) becomes,
10U + 2V = 4-------(3)
15U - 5V = -2-------(4)
From equation (3) we get,
10U + 2V = 4
10U = 4-2V
U = 4-2V/10-------(5)
Putting the value of U in equation (4)
15U - 5V = -2
15 × (4-2V/10) - 5V = -2
3(4-2V/2) - 5V = -2
12 - 6V/2 - 5V = -2
12 - 6V - 10V = -2 × 2
-16V +12 = -4
-16V = -4-12
-16V = -16
V = -16/-16 = 1
Putting the value of V in equation (5)
U = 4-2V/10 => 4 - 2 × 1/10 = 4-2/10 = 2/10
U = 2/10 = 1/5
1/X+Y = U
1/X+Y = 1/5
5 = X + Y
X + Y = 5---------(6)
And,
1/X - Y = V
1/X-Y = 1
X - Y = 1-----------(7)
From equation (6) we get,
X + Y = 5
X = 5-Y------------(8)
Putting the value of X in equation (7)
X - Y = 1
5-Y -Y = 1
-2Y = 1-5
-2Y = -4
Y = -4/-2 => 2
Putting the value of Y in equation (8)
X = 5-Y => 5-2 = 3
Hence,
X = 3 and Y = 2
HOPE IT WILL HELP YOU....... :-)
10/X+Y + 2/X-Y = 4-------(1)
15/X+Y - 5/X-Y = -2--------(2)
Let 1/X+Y = U and 1/X-Y = V . Then equation (1) and equation (2) becomes,
10U + 2V = 4-------(3)
15U - 5V = -2-------(4)
From equation (3) we get,
10U + 2V = 4
10U = 4-2V
U = 4-2V/10-------(5)
Putting the value of U in equation (4)
15U - 5V = -2
15 × (4-2V/10) - 5V = -2
3(4-2V/2) - 5V = -2
12 - 6V/2 - 5V = -2
12 - 6V - 10V = -2 × 2
-16V +12 = -4
-16V = -4-12
-16V = -16
V = -16/-16 = 1
Putting the value of V in equation (5)
U = 4-2V/10 => 4 - 2 × 1/10 = 4-2/10 = 2/10
U = 2/10 = 1/5
1/X+Y = U
1/X+Y = 1/5
5 = X + Y
X + Y = 5---------(6)
And,
1/X - Y = V
1/X-Y = 1
X - Y = 1-----------(7)
From equation (6) we get,
X + Y = 5
X = 5-Y------------(8)
Putting the value of X in equation (7)
X - Y = 1
5-Y -Y = 1
-2Y = 1-5
-2Y = -4
Y = -4/-2 => 2
Putting the value of Y in equation (8)
X = 5-Y => 5-2 = 3
Hence,
X = 3 and Y = 2
HOPE IT WILL HELP YOU....... :-)
meetshah4242:
THANKS
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