(1) 100 g of hard water contains 0.00475 g MgCly. What is the hardness of water in ppm?
50 ppm
5 ppin
500 ppm
475 ppini
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Answer:
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Explanation:
Total hardness= Ca hardness + Mg hardness
The calcium and Mg hardness is the concentration of Ca & Mg ions expressed as equivalents of CaCO
3
For Mg=
M
Mg
M
CaCO
3
=
24.3
100.1
=4.1
So total hardness= 4.1[Mg
2+
]ppm of CaCO
3
Given 100kg of water contains 5g MgSO
4
i.e, 100L water contains 500mg of MgSO
4
=
M
MgSO
4
(500mg)24.3
=
120.7
(500mg)(24.3)
=100mg of Mg ims
∴[Mg
2+
]=100mg/100L=1mg/L
So hardness of water= 4.1[1mg/L]
=4.1ppm of CaCO
3
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