Question

1
11
2' yʻ+1
+1) log
2
2
log(y² +,1)+ log (x + 1) = log C
(y² + 1)(x+1) =
ñ
e 3. Solve
dy_x( 2 log x +1)
dx siny + y cosy
h. We have,
dy_x(2 log x+1)
dx siny + y cosy
ny + y cosyldy = {x( 2 log x+1)}dx
tegrating both the sides, we get
ny+y cosy)dy = kx(2 log x+1)}dx+
+y siny-ſch-siny dy = 2 log x-xdx+​

Answer 1

Answer:

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