(1) [(11 + 7) x (7 + 3)] (mod 7)
4
7
25
5
2 . (46 + 37)(mod 7)
3
6
5
2
3. (6 + 5) (mod 6)
5
4
3
2
4. 2x = 3 (mod. 4)
1
2
3
No Solution
5. -2 (mod 4)
1
2
3
4
6. 56 (mod. 7)
0
1
2
3
7. (10 - 7) (mod 6)
1
2
3
4
8. (15 – 53) (mod 4)
-8
-38
2
20
9. 3 + 221 in 7-day clock arithmetic
0
1
2
3
10. [(3 x 7) – 5] (mod 4)
0
1
2
3
10. 7 - 16 in 12-hour clock arithmetic
1
2
3
4
11. [(4 – 9) x 7] (mod 5)
0
1
2
5
3
12. 2x = 1 (mod 3)
{2, 6, 10, 14, …}
{1, 4, 7, 10, …}
{2, 5, 8, 11, …}
None
13. 8 + 10 in 12-hour clock arithmetic
18
6
12
2
14. 2x = 8 (mod 10)
{4, 9, 14, 19, 24, 29, …}
{4, 14, 24, …}
{9, 19, 29, …}
None
please show your workings
first gets the brainliest answer
Answers
Answered by
1
Answer:
I don't know this answer
Similar questions