1.11 defective bulbs are accidentally mixed with 121 good ones. One ball is taken out at random from this lot. Find the probability that the ball taken out is a good one. 1. 1/12 2. 7/12 3. 11/12 4. 1/11
Answers
Answered by
6
probability = No. of favorable outcomes / total number of outcomes
P(good bulb) = 121-11/121 = 110/121 = 10/11
P(good bulb) = 121-11/121 = 110/121 = 10/11
devanshim2003:
I think the answer is wrong pls check
Answered by
6
Answer:
Step-by-step explanation:
No. Of defective bulbs = 11
No of good ones =121
Total bulbs=121+11
=132
E=probability of taking the good one
P(E)=no.of events occurred/total no. of events
= 121/132
= 1/11
Hope this answer is clear for you if it made you happy and also if the answer is right pls... Mark me as brainlylist.....pls.. hope the spelling is wrong
Similar questions