Question

1.11 grams of Cacl2 is added to water terming 20 ml of this solution is
taken and diluted 10 folds find on the no. of
moles of cl- in diluted
solution ?​

Answer 1

Answer:

1.11

111

=

0.01

m

o

l

C

a

C

l

2

Answer 2

Answer:

1.11 g CaCl2 x 1 mole/111 g = 0.01 moles CaCl2

0.01 moles CaCl2/500 ml x 2 moles Cl-/mole CaCl2 = 4x10-5 moles Cl-/ml

Diluted this 10 fold = 4x10-6 moles Cl-/ml

In 2 mls you have 4x10-6 moles Cl-/ml x 2 ml = 8x10-6 moles Cl-