1
111. In a small electric plant at your home, 45 kJ
energy is generated. Then how long you can
power a incandescent bulb of 45W
approximately?
(A) 45 min
(B) 16.67 min
(C) 20-25 min (D) 45 sec
Baronb.
Answers
Answered by
2
Answer:
(B)16.67 min
Step-by-step explanation:
W = 45kJ = 45000 J
P = 45 W
W = P × t
t = W/P
t = 45000/45
t = 1000 sec
t = 16.67 min
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Answered by
0
Answer: option b
Step-by-step explanation: plz see the attachment
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