Question

1.
11th term of the AP: -3,
2,..., is
a) 28
b) 22
c) -38
d)-48​

Answer 1

Answer: 47

First term(a)=  -3

Common difference(d) = 2-(-3)

                                  = 5

11th term= a₁₁

a₁₁ = a + 10d

a₁₁= -3 + 10*5

   = -3+ 50

   = 47

Hence the answer is 47.

Answer 2

The given A.P is -3, 2 , .......

t1 = a = -3, d = 2-(-3) = 2+3 =5

.°. tn = a + (n–1) d

t11 = (-3) + (11–1) 5

= (-3) + (10 × 5)

= (-3) + 50

= 47

.°. The 11th term of an A.P is 47