Math, asked by shahdev10a13, 30 days ago

1/12(log10x)^2=1/3-1/4(log10x)
please provide solution of this. value of x​

Answers

Answered by gurjarmamta312
0

500 kg =1000 km okk thanks you

Answered by shrmaop6
0

Answer:

Equation log simplification.

User

(1/12)(logx)=(1/3)-(1/4) (log10x

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To solve this equation, we can start by simplifying the logarithmic expressions on both sides of the equation using the following logarithmic identities:

log a^b = b log a

log a + log b = log ab

log a - log b = log(a/b)

Applying these identities, we can simplify the equation as follows:

(1/12)log(x) = (1/3) - (1/4)log(10x)

(1/12)log(x) = (1/3) - (1/4)(log(10) + log(x)) [using log a + log b = log ab]

(1/12)log(x) = (1/3) - (1/4)(1 + log(x)) [using log(10) = 1]

Next, we can simplify the right-hand side of the equation by multiplying both sides by 12 to eliminate the fractions:

log(x) = 4 - 3(1 + log(x))

log(x) = 4 - 3 - 3log(x)

4log(x) = 1

log(x) = 1/4

Finally, we can solve for x by taking both sides of the equation to the power of 10:

x = 10^(log(x)) = 10^(1/4) = 1.77828

Therefore, the solution to the equation is x ≈ 1.77828.

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