Question

1.12 mL of a gas is produced at STP by the action of 4.12 mg of alcohol, ROH, with methylmagne
iodide. The molecular mass of alcohol is
1) 16 u
2) 41.2 u
3) 82.4
1)
4) 156 u
​

Answer 1

The molar mass is 41.2u

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Answer 2

Answer:

Answer: Molecular mass of alcohol is 82.4.

Explanation:

ROH + CH3MgI⟶ --------> CH4 + MgROI

22400mL of CH4 produced at STP

= 1mol of ROH

1.12mL of CH4 produced at STP = 1.12

/ 22400= 5×10−5 mol

Now molecular mass of ROH = 4.12×10^-3 /5*10^−5

∴ mol mass of ROH=82.4.

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