Question

1.12 ml of gas is produced at STP by the action of 0.142 mg of alcohol are watch with methyl magnesium iodide the molecular mass of alcohol is

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Answer 1

Answer:

82.4g

Explanation:

ROH+CH3MgI⟶CH4+MgROI

22400mL of CH4 produced at STP

= 1mol of ROH

1.12mL of CH4 produced at STP =224001.12 mol

Now molecular mass of ROH =5×10−54.12×10−3

∴ mol mass of ROH=82.4

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