1.12L CO2gas at S.T.P.+0.44 g CO2-6.02*10^21molecules of co2=_____moles of CO2
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Answer: 0.05 moles of CO2
Explanation: 1.12L CO2 =.05 moles
0.44 g CO2 =10^-2 moles
6.02 x 10^21 molecules of CO2 =10^-2 moles
now according to question
0.05 +10^-2 -10^-2 =0.05
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