Math, asked by karunaray82, 1 month ago

1 13. Find the value of the expressions : (

16x2 + 24xy +9y2, when x=1/2 when y=1/3

Answers

Answered by Eutuxia
2

Given :

  • Expression = 16x2 + 24xy +9y2
  • x = 1/2
  • y = 1/3

To find :

  • the value of the expressions.

Solution :

⇒ Let's find the value of the expression.

\sf \longrightarrow 16 \times \dfrac{1}{2}  \times 2 + 24 \times \dfrac{1}{2}   \times \dfrac{1}{3} + 9 \times \dfrac{1}{2}   \times 2

\sf \longrightarrow \dfrac{16}{2}  \times 2 + 24 \times \dfrac{1}{2}  \times \dfrac{1}{3} + 9 \times \dfrac{1}{3}  \times  2

\sf \longrightarrow 8 \times 2 + 24 \times \dfrac{1}{2}  \times  \dfrac{1}{3} + 9 \times  \dfrac{1}{3}  \times 2

\sf \longrightarrow 8 \times 2 + 24 \times  \dfrac{1 \times 1}{2 \times 3}  \times 3 + 9 \times \dfrac{1}{3}  \times 2\\

\sf \longrightarrow 8 \times 2 + 24 \times \dfrac{1}{6}  + 9 \times \dfrac{1}{3}  \times 2

\sf \longrightarrow 8 \times 2 + 24 \times \dfrac{1}{6}  +  \dfrac{ 9}{3}  \times 2

\sf \longrightarrow 8 \times 2 + 24 \times \dfrac{1}{6}  +  3}  \times 2

\sf \longrightarrow 8 \times 2 +   \dfrac{24}{6}  +  3}  \times 2

\sf \longrightarrow 8 \times 2 + 4 +  3}  \times 2

\sf \longrightarrow 16 + 4 +  3}  \times 2

\sf \longrightarrow 20 +  3}  \times 2

\sf \longrightarrow 20 +  6

\sf \longrightarrow 26

  • Therefore, the value of 16x2 + 24xy +9y2 is 26.
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