Math, asked by criseldadavid470, 2 months ago

1 - 14. Ajar contains 20 small balls numbered 1 to 20. If a ball is drawn randomly fr
robability that it is
11. P (9 or 17)

12. P (11 or divisible by 4)

13. P (odd or divisible by 5)

14. P (a number divisible by 3 or divisible by 4)

Answers

Answered by anonymous3851
0

Answer:

P(9 or 17) = 2/20=1/10

P (11 or divisible by 4) = 5/20=1/4

P (odd or divisible by 5)=10/20 + 4/20 = 14/20 = 7/10

P (a number divisible by 3 or divisible by 4) = 6/20 + 5/20=11/20

Answered by jaimatadi123467890
0

Answer:

listen Sathish question

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