1 - 14. Ajar contains 20 small balls numbered 1 to 20. If a ball is drawn randomly fr
robability that it is
11. P (9 or 17)
12. P (11 or divisible by 4)
13. P (odd or divisible by 5)
14. P (a number divisible by 3 or divisible by 4)
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Answer:
P(9 or 17) = 2/20=1/10
P (11 or divisible by 4) = 5/20=1/4
P (odd or divisible by 5)=10/20 + 4/20 = 14/20 = 7/10
P (a number divisible by 3 or divisible by 4) = 6/20 + 5/20=11/20
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Answer:
listen Sathish question
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