Question

1
14. The perimeter of an isosceles triangle is 42 cm and its base is 15 times
each of the equal sides. Find (i) the length of each side of the triangle,
(ii) the area of the triangle, and (iii) the height of the triangle. (Given,
V7 = 2.64.)
ne 6
2 p.​

Answer 1

Given

Let ABC be the given isosceles triangle.

Where AB = AC = x ( say)

So, let BC be 15x

Construction,

Draw AD perpendicular on BC such that AD is its height.

To find (I)

Perimeter of triangle ABC

AB + BC + AC = 42 cm

X + 15x + x = 42

17x = 42

X = 2.4

So AC = 2.4 cm

AB = 2.4 cm

BC = 36 cm

I hope my answer will help you.