1.15
g of metallic Na react with excess of
water.
How many males of H2 are
formed and what volume of H2 is
formed at S.T.P?
Answers
Answered by
5
Explanation:
2Na + 2H2O ---------> 2NaOH + H2
From the balanced equation, 2 moles of sodium metal (Na) produces one mole of hydrogen gas (H2).
Therefore (2X23) g of Na produces 1 mole of hydrogen. 1.15g of Na will produce;
(1.15x1)/46= 0.025 moles of hydrogen.
Molar gas volume at stp is 22.4 L.
Therefore 0.025x 22.4
=0.56 L of hydrogen are produced
Similar questions