1.15g of metallic Na reacts with excess of water. How many moles of H2 are formed and what volume of H2 is formed at S.T.P
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One mole of sodium atom weighs 23 g
1.15 g of sodium atoms have: 1.15/23 = 0.05 moles
2Na + 2H₂O = 2NaOH + H₂
0.05 moles of Na will react with 0.05 moles of water to give 0.05 moles of NaOH and 0.05/2 = 0.025 moles of Hydrogen
Volume of Hydrogen formed = 0.025 x 22.4 = 0.56 L of hydrogen gas is produced
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