Question

1
16. A object is thrown with initial speed
5 m s-1 with an angle of projection 30°.
What is the height and range reached by
the particle?​

Answer 1

Answer:

initial speed=5m/sec

angle of projection=30 °

h=?

H=,I*sin

Answer 2

Answer:

Horizontal range will be 2.206m and height will be 3062.5m

Step-by-step explanation:

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