Question

1.16 g sodium chloride should react with how much silver nitrate to form 1.7g sodium
nitrate and 2.87g silver chloride ?​

Answer 1

Answer:

3.4 g

Explanation:

NaCl + AgNO3 -----> AgCl + NaNO3

58.5 + 170 ----> 143.3 + 85

Given masses, 1.16 + x ------> 2.87 + 1.7

Comparing AgNO3 and NaNO3 from both reactions,

170 ----> 85

x -----> 1.7

By cross multiplication,

x = 3.4 g

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