Question

1-169a²

solve the following ​

Answer 1

Step-by-step explanation:

this is your answer

i hope it is helpful for you

Answer 2

hope it hepls

Step-by-step explanation:

1-169$a^{2}$ = 0                     lets assume

-169$a^{2}$ = -1

$a^{2}$ = -1+169

$a^{2}$ = 168

if we transpose root to rhs it becomes root

a= $\sqrt{168}$