Question

(1)
17. The altitudes BN and CM of AABC meet at H. Prove that
(ii) triangleMHN is similar to triangleBHC.
(iii)HC/HB=ГCN.HN/BM.HM

(i) CN. HM e BM . HN (in)
the altitude bn and cm of triangle abc meet at h prove that

Answer 1

b)we know HC/HB=CN/BM an we also know HC/HB=HN/HM.. multiplying both equation we get (HC/HB)^2=CN. HN/BM. HM

HC/HM=(CM. HN/BM. HM)^1/2
HENCE PROVED

Answer 2

Answer:

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