Question

1.179 gram of copper on heating in air gap 1.476 gram of black oxide of copper 1.375 gram of black copper oxide on reduction with hydrogen gave 1.098 gram of copper. Show that these results illustrate the law of constant proportion? ​

Answer 1

Answer:1.179 gram of copper on heating in air gap 1.476 gram of black oxide of copper 1.375 gram of black copper oxide on reduction with hydrogen gave

Answer 2

Answer:

2.42 gms of copper gives 3.025 gms of black oxide(CuO)

=> percentage of copper in cuo = 2.42/3.025  x 100 = 80%

=> percentage of oxygen in cuo = 100 - 80 = 20 %

Ratio of copper : oxygen = 80 : 20 = 4:1

Similarly ,

6.49 gms of black oxide gave 5.192 gm of copper

=> Percentage of copper in cuo = 5.192/6.49  x 100 = 80 %

percentage of oxygen in cuo = 100 - 80 = 20 %

Ratio of copper : oxygen = 80 : 20 = 4:1

Hence in both the reactions the ratio of copper : oxygen is same

Hence these figures are in accordance with law of constant proportion