Question

1
18.
sec A - tan A
sec A + tan A​

Answer 1

Answer:

1-sinA÷cosA answer for secA-tanA

1+sinA÷cosA answer for secA+tanA

HINT FOR ANSWER IS

SECA= 1÷COSA

TANA= SINA÷COSA

Answer 2

Step-by-step explanation:

LHS:

=1/(secA -tanA)

=1/(secA +tanA)×(secA-tanA)/(sec A- tan A)

=(sec A- tan A)/ (sec²A- tan²A)

= sec A - tan A / 1

= sec A - tan A

= RHS

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