Question

1.18 Suppose the spheres A and B in Exercise 1.12. have identical sizes.
A third sphere of the same size but uncharged is brought in contact
with the first, then brought in contact with the second, and finally
removed from both. What is the new force of repulsion between A
and 112​

Answer 1

Answer:

When an uncharged sphere is brought in contact with sphere A, half of the charge will be shifted to third sphere. So the charge q1 on sphere A becomes 3.25x10‒7 C.

Again on contact of sphere C with sphere B, redistribution of charge will happen and charge q2 on sphere B gets [{(6.5+3.25) × 10‒7}/2 =] 4.875x10‒7 C.

Then, by the same formula for force, we get

F = [(9x109).(q1.q2)] / r2

F = 5.7x10⁻³ N.

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