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19. The modulus of the vector is product of two vector is 1÷3 times their scalar product. the angle between vector is:
(a) pie÷6
(b) pie÷2
(c) pie÷4
(d) pie÷3
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Explanation:
Answer
Correct option is
C
3
π
According to the question,
∣
A
×
B
∣=
3
∣
A
.
B
∣
Expanding the vector and the dot products:
ABsinθ=
3
ABcosθ
⇒tanθ=
3
⇒θ=60
∘
=
3
π
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