Question

1.1g of an unknown gas occupies 0.56L at STP. the gas may be​

Answer 1

Answer:

Co2

Explanation:

0.56L is occupied by 1.1g gas

1L by 1.1/0.56g gas

22.4 by 1.1/0.56 *22.4 =44g

Answer is Co2 (Molar mass=44g)

Answer 2

Answer:

The gas is Carbon Dioxide$(CO_{2})$

Explanation:

Given data is,

Mass of gas is $m=1.1gm$

Volume occupied by gas is $V=0.56L$

We know that at Standard temperature and pressure,one mole of any gas occupies a volume of 22.4L.

Therefore,the molar mass of the given gas is the mass at which the gas occupies a volume of 22.4L.

As 1.1gm of gas occupies 0.56L,

The mass of gas which occupies 22.4L is $\frac{22.4}{0.56} \times 1.1=44gm$

Hence the molar mass of gas is found to be 44gm.

Therefore,

The gas is Carbon Dioxide$(CO_{2})$

#SPJ2