Question

1/1point
.
एका आयताची परिमिती 40 सेमी आहे.
आयताची लांबी ही रुंदीच्या दुपटीपेक्षा2 ने जास्त
आहे तर आयताची लांबी व रुंदी किती?​

Answer 1

Given:

The perimeter of a rectangle is 40 cm.

The length of the rectangle is more than double its breadth by 2.

To find:

The length and breadth

Solution:

Let's assume "l" cm & "w" cm are the length and breadth of the rectangle.

The length of the rectangle is more than double its breadth by 2, so we can form an equation as:

$l = 2b + 2$ .... (i)

We know,

$\boxed{\bold{Perimeter \:of\:a\: rectangle = 2[l + b]}}$

Therefore, according to the question, we get

$2[l+b] = 40$

on substituting from (i), we get

$\implies 2 [2b+2 + b] = 40$

$\implies [2b+2 + b] = 20$

$\implies 3b+2 = 20$

$\implies 3b = 20 - 2$

$\implies b = \frac{18}{3}$

$\implies \bold{b = 6 \:cm}$

∴ $l = (2\times 6) + 2 = 12 + 2 = \bold{14\:cm}$

Thus,

The length of the rectangle → 14 cm.

The breadth of the rectangle → 6 cm.

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Answer 2

Step-by-step explanation:

हे हे का आयताची परिमिती 40 सेंटीमीटर आहे आयताची लांबी रुंदीच्या दुपटीपेक्षा जास्त आहे त्याची लांबी व रुंदी किती