-1.2 ,0.8,2.8 is an A P
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Answer:
here
Let
1st term = -1.2, 2nd term = 0.8 and 3rd term = 2.8
Now, in an AP the difference of nth term and (n -1)th term is always equal
So, in the given AP
2nd term - 1st term = 0.8 - (-1.2) = 0.8+1.2 = 2.0
Now
3rd term - 2nd term = 2.8 - 0.8 = 2.0
So here the difference is equal
So the given terms are in AP.
I hope it will help.
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