Question

-1.2,0.8,2.8 ..... is an AP or not​

Answer 1

Answer:

yes it is an ap beacause

Step-by-step explanation:

2.8-0.8=2

0.8-(-1.2)=2

so, the valve of d is same at both the points so,it is an ap

Answer 2

Answer:

t1= -1.2

t2=0.8

t3=2.8.

therefore ... d=t2 -t1

d=0.8+(-1.2)

d= -0.4

similarly d=t3-t2

d=2.8-0.8

d=2.0

here no Common differance

so, is it not in AP