1/√2 =0
find the nature of the root
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Answer:
x2−3x+5=0a=2,b=−3,c=5
Discriminant, D=b2−4ac=9−40=−31
Since D<0, the roots are imaginary for the given equation.
ii)
3x2−43x+4=0a=3,b=−43,c=4
Discriminant, D=b2−4ac=48−48=0
Since D=0, the roots are real and equal for the given equation.
3x2−43x+4=0a=3,b=−43,c=4x=2a[−b±b2−4ac]x=643=32
iii)
2x2−6x+3=0
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