Math, asked by 975457ta, 4 months ago

1/√2 =0
find the nature of the root​

Answers

Answered by SARASHAIKH32
0

Answer:

 

x2−3x+5=0a=2,b=−3,c=5

Discriminant, D=b2−4ac=9−40=−31

Since D<0, the roots are imaginary for the given equation.

ii) 

3x2−43x+4=0a=3,b=−43,c=4

Discriminant, D=b2−4ac=48−48=0

Since D=0, the roots are real and equal for the given equation.

3x2−43x+4=0a=3,b=−43,c=4x=2a[−b±b2−4ac]x=643=32

iii) 

2x2−6x+3=0

Answered by rashishnayak599
1

Answer:

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