1/√2
____
1 + 1× 1
_ _ _
√2 √2 2
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Answer:
( 21+i ) 8n+( 21−i ) 8n=[( 21+i ) 2 ] 4n +[( 21−i ) 2 ] 4n=( ( 2 ) 22i ) 4n +( ( 2 ) 2−2i ) 4n=(i) 4n +(−i) 4n=1+1=2
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