Question

(1/2)-¹+(1/3)-¹+(1/3)-¹
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Answer 1

Answer: $(\frac{1}{2})^{-1} +( \frac{1}{3} )^{-1} + \frac{1}{3} ^{-1} = 8$

$= (\frac{1}{2})^{-1} +( \frac{1}{3} )^{-1} + \frac{1}{3} ^{-1}$

$= (\frac{2}{1} )^1 + (\frac{3}{1}) ^1 + (\frac{3}{1}) ^1$                                         $Identity:[a^{-m} =( \frac{1}{a} )^m]$

= 2 + 3 + 3

= 8

Hope you understood.

Thank You.