1/2÷[-1/3]€[1/2÷-1/5]÷2/5
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false_(a) 3 € {2,4,6,8} false_(b) 0 € false (c) {1} € {1, 2, 3} true_(d) {2} S {1, 2, 3} true (e) {1, 3, 5, 7, 9) = {1, 5, 9, 3, 7) false_(f) {1,3,5, 9) = {1,3 ..
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