1/2+1/6+1/12+1/20+1/30+......1/n(n+1) = ?
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Answer:
=> 1/2 + 1/6 + 1/12 + 1/20 + 1/30 + ......
.......+ 1/n(n+1)
=> 1/1•2 + 1/2•3 + 1/3•4 + 1/4•5 + 1/5•6+
................+ 1/n(n+1)
=> (2-1)/1•2 + (3-2)/2•3 + (4-3)/3•4 +
(5-4)/4•5 + (6-5)/5•4 +............
............+ {(n+1)-n}/n•(n+1)
=> (1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) +
(1/4 - 1/5) + (1/5 - 1/6) + ..........
...........+ {1/n - 1/(n+1)}
=> 1 - 1/(n+1)
=> (n+1-1)/(n+1)
=> n/(n+1)
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