Math, asked by akshyap, 11 months ago

1/2+1/6+1/12+1/20+1/30+......1/n(n+1) = ?

Answers

Answered by Anonymous
4

Answer:

=> 1/2 + 1/6 + 1/12 + 1/20 + 1/30 + ......

.......+ 1/n(n+1)

=> 1/1•2 + 1/2•3 + 1/3•4 + 1/4•5 + 1/5•6+

................+ 1/n(n+1)

=> (2-1)/1•2 + (3-2)/2•3 + (4-3)/3•4 +

(5-4)/4•5 + (6-5)/5•4 +............

............+ {(n+1)-n}/n•(n+1)

=> (1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) +

(1/4 - 1/5) + (1/5 - 1/6) + ..........

...........+ {1/n - 1/(n+1)}

=> 1 - 1/(n+1)

=> (n+1-1)/(n+1)

=> n/(n+1)

Attachments:
Similar questions