Question

1/2×+1/x×y=2 ,
1/3×x+1/2y=13/6​

Answer 1

Answer:

1/2+1/x×y=2

or, 1/2+y/x=2

or, y/x=2-1/2

or, y/x=3/2

or, 2y=2x

or, 2x-2y=0_________(i)

1/3×x+1/2y=13/6

or, x/3+1/2y=13/6

or, 6x/3+6/2y=13×6/6 (×6 in each side)

or, 2x+3/y=13___________(ii)

Using corruption step,

2x-2y=0

2x+3/y=13 ['-'step]

- - -

________________________

2x-2x-2y-3/y=-13

or, 0-(2y²-3)=-39

or, 2y²-3=39

or, 2y²= 36

or, y²=18

or, y=(+-)3^2(we should put the positive reading for our

So, After putting the value of y in the equation (i), we get,

2x-2y=0

or, 2x-2*3^2=0

or, 2x-6^2=0

or, 2x=6^2

or, x= 3^2

SO THE ANSWER IS,

X=3^2, Y=3^2