Question

1/2(10-4x)-1/4(4x+12)=0 find value for x​

Answer 1

Answer:

Here is your answer: 2/3

Answer 2

Answer:

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Step-by-step explanation:

$\large \frac{1}{2} (10 - 4x) - \frac{1}{4} (4x + 12) = 0 \\ \\ \large \frac{10 - 4x}{2} - \frac{4x + 12}{4} = 0 \\ \\ \large \: taking \: \: lcm \\ \\ \large \frac{(10 - 4x) \times 2}{2 \times 2} - \frac{4x + 12}{4} = 0 \\ \\ \large \frac{20 - 8x}{4} - \frac{4x + 12}{4} = 0 \\ \\ \large \frac{20 - 8x - (4x + 12)}{4} = 0 \\ \\ \large \frac{20 - 8x - 4x - 12}{4} = 0 \\ \\ \large \frac{20 - 12 - 8x - 4x}{4} = 0 \\ \\ \large \frac{ 8 - 12x}{4} = 0 \\ \\ \large8 - 12x = 0 \\ \\ \large8 = 12 x \\ \\ \large x = \frac{8}{12} \\ \\ \large\bold\red{\therefore \: x = \frac{2}{3} }$