Question

1/2+{19/4-(19/6-7/3)}​

Answer 1

Answer:

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$\frac{1}{2}+ [4\frac{3}{4}-(3\frac{1}{6}-2\frac{1}{3})]\\=\frac{1}{2}+[\frac{19}{4}-(\frac{19}{6}-\frac{7}{3})]\\=\frac{1}{2}+[\frac{19}{4}-(\frac{19-14}{6})]\\=\frac{1}{2}+[\frac{19}{4}-\frac{5}{6}]\\=\frac{1}{2}+[\frac{57-10}{12}]\\=\frac{1}{2}+\frac{47}{12}\\=\frac{6+47}{12}=\frac{53}{12}$