Math, asked by kavitachandak83, 5 months ago

[(1/2)^-2+(2/3)^2+(4/3)^0]^-2 please help me in this question ​

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Answered by dilliprasaddhakal528
0

[(1/2)⁻²+ (2/3)²+(4/3)⁰]⁻²

= [(2/1)²+4/9+1]⁻²

= [4+4/9+1]⁻²

= [5+4/9]⁻²

= [(45+4)/9]⁻²

= (49/9)⁻²

= (9/49)²

= 81/2401 Ans.

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