Math, asked by dipzz2411, 1 year ago

1^2+2^2+3^2+........+50^2=?​

Answers

Answered by pratiksha2217
1

37408 is the answer

hope it helps


dipzz2411: no wrong
dipzz2411: its a formula
dipzz2411: n (n+1)(2n+1)/6
dipzz2411: n= put the last number
Answered by GURVINDERSINGH01
0

Answer:

Step-by-step explanation:

for solving 1^{2}+2^{2}+3^{2}+.........+50^{2}\\use formula, 1^{2}+2^{2}+3^{2}+........+n^{2}= n(n+1)(2n+1)/6\\\\= 50(50+1)(2*50+1)/6= (50*51*101)/6= 42925\\\\Hope this helps

Similar questions