Question

1^2+2^2+3^2+...........+n^2>n^3/3

Answer 1

Answer:

yes

Step-by-step explanation:

this will come out to be

$\frac{n(n+1)(2n+1)}{6}$>$\frac{n^3}{3}$

which simplifies to

n^2 /3 +n/6>0